Finding Final Temp. Distribution After Thermal Equilibrium

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SUMMARY

The discussion focuses on determining the final temperature distribution after thermal equilibrium in an isolated system comprising two materials. The initial energy calculations for Material 1 and Material 2 are given as 4500W and 10000W, respectively. The correct approach involves conserving energy rather than temperature, leading to the conclusion that the system reaches a uniform temperature when internal energy is constant. The final temperatures calculated are 72.5°C for Material 1 and 36.25°C for Material 2, highlighting the importance of using Joules for energy and Kelvin for temperature in thermodynamic calculations.

PREREQUISITES
  • Understanding of thermodynamics principles, specifically thermal equilibrium.
  • Knowledge of energy conservation in isolated systems.
  • Familiarity with specific heat capacity (Cp) calculations.
  • Basic understanding of temperature units, particularly Kelvin and Celsius.
NEXT STEPS
  • Study the laws of thermodynamics, focusing on the conservation of energy.
  • Learn about specific heat capacity and its role in thermal energy calculations.
  • Explore the concept of entropy and its relationship with thermal equilibrium.
  • Investigate the differences between energy units (Joules vs. Watts) and temperature scales (Celsius vs. Kelvin).
USEFUL FOR

Students and professionals in physics, engineering, and thermodynamics who are interested in understanding thermal equilibrium and energy conservation principles in isolated systems.

niazaliahmed
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The above diagram shows the problem description.

I have to find the final temperature distribution after thermal equilibrium.

I am assuming that the thermal energy is conserved but not the temperature.(Correct me if I am wrong)

Energy of the materials at initial state is (Refer Image)

For material 1 - m.Cp.T = 100*1*45 W = 4500W
For material 2 - m.Cp.T = 200*1*50 W = 10000W

So the system would achieve equilibrium when the energy in both material are same i.e. 7250W

If that happens Material 1 would be at a temperature of 72.5 C
Material 2 would be at a temperature of 36.25 C

I know that this method is wrong indeed. But can anyone explain me why we would conserve the temperature instead of energy of the system??
 
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For starters the correct unit of energy is Joules(J) not Watts(W). The correct unit of temperature is Kelvin(K) not Celsius(C). If I remember correctly you add 273 to a temperature in C to get it into K.

Since the system (meaning both blocks) is isolated, the the total internal energy must remain constant. An isolated system will eventually reach a state of maximum entropy (and therefore uniform temperature).

So the initial energy in the system is:

m1c1T1 + m1c1T2 = a constant

and after reaching equilibrium

(m1c1+m2c2)T = the same constant

thus equate the two and solve for T.
 
That was helpful, thanks
 

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