Finding Force Given Angle: A Last-Minute Attempt

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The discussion focuses on finding the force as a function of angle θ, with the derived equation being F(θ) = (μmg)/(cos(θ) + μsin(θ)). A user expresses frustration in solving for the angle, realizing that the task does not require finding an angle at all. Instead, the correct approach involves equating magnetic force to friction force and solving for the magnetic field strength B. Additionally, the direction of the force is determined using the right-hand rule, indicating it must be perpendicular to both the current and the slide. The conversation emphasizes clarity in problem requirements and the importance of using appropriate formulas.
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Homework Statement



Screen_Shot_2011-10-24_at_11.23.33_PM.png


Homework Equations



this is what i think i figured out to be the equation for force as a function of θ:

F(θ) = (μmg)/(cos(θ) + μsin(θ))

The Attempt at a Solution



I tried to find extrema using the numbers given to figure out the angle, but the number i am getting is not right. This is kind of a last ditch effort as I need to finish this within a half hour
 
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You aren't asked to find an angle. Don't use any formula with an angle in it! For the magnitude, start out with "magnetic force = friction force" and fill in details until you can solve it for B.
For the direction, apply your hand rule to the lower diagram. The answer will be up or down (which you must translate into y or -y) because it must be perpendicular to both the current and the slide.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

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