Finding Force of Friction - Tug of War Problem

Click For Summary
In the tug of war problem, Joe exerts a pulling force of 200 N while Bill skids toward him at constant velocity, indicating no net acceleration. The force of friction between Bill's feet and the ground must equal Joe's pulling force to maintain this constant velocity, which is 200 N. Therefore, the correct answer to the problem is that the force of friction is 200 N. Drawing a free body diagram is recommended for visualizing the forces involved. Understanding Newton's second law is crucial for solving such problems effectively.
rocapp
Messages
95
Reaction score
0

Homework Statement


Joe and Bill are playing tug of war. Joe is pulling with a force of 200 N. Bill is simply hanging on, but skidding toward Joe at a constant velocity. What is the force of friction between Bill's feet and the ground?

A) Greater than 200N but less than 400N
B) Less than 200N
C) 400N
D) 200N

Homework Equations


[Kinetic Frictional Force] = μkF


The Attempt at a Solution


Since Joe is pulling with a force of 200N and there is no acceleration (constant velocity), the net force is zero. The kinetic frictional force should be equal to 200N.
 
Physics news on Phys.org
Yep, you got it. Whenever you're presented with one of these problems involving Newton's second law, the best thing to do is to draw a free body diagram and think of the net force on the object. It looks like that's how you went at this problem, so keep it up!
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 4 ·
Replies
4
Views
9K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
10K
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 42 ·
2
Replies
42
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 41 ·
2
Replies
41
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K