Finding Fourier extension and if it converges

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Weilin Meng
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Homework Statement


Let f(x) = sin(x)/x for |x| <= pi with the obvious definition at x = 0

Extend it periodically. Will the Fourier series converge at x=0?

Homework Equations


Fourier coefficients:

ao = 1/\pi \int_{-\pi}^{\pi} (sin(x)/x)

an = 1/\pi \int_{-\pi}^{\pi} (sin(x)/x) * cos(nx)

bn = 1/\pi \int_{-\pi}^{\pi} (sin(x)/x) * sin(nx)

The Attempt at a Solution



ao = 1/\pi \int_{-\pi}^{\pi} (sin(x)/x) = 2Si(pi)/pi

an = 1/\pi \int_{-\pi}^{\pi} (sin(x)/x) * cos(nx) = (-Si((n-1)pi) + Si((n+1)pi))/pi

bn = 1/\pi \int_{-\pi}^{\pi} (sin(x)/x) * sin(nx) = 0

So the Fourier series will be:
f(x)=1/\pi*Si(\pi)+\sum_{1}^{\infty }1/\pi(-Si((n-1)\pi) + Si((n+1)\pi)

at x=0 because cos(n(0)) = 1

I figured that:
\sum_{1}^{\infty }1/\pi(-Si((n-1)\pi) + Si((n+1)\pi)
Will converge to zero and we get f(x) = si(pi)/pi...

I don't know what si(pi)/pi is but I don't think that converges to 1 as sin(x)/x does at x=0...did i mess up anything?
 
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bump, nobody yet? Am I not providing anything?
 
I'm not too familiar with the sine integral function, but seeing how your summand consists of a difference of two evaluations (and the arguments have a fixed difference! Surely that will help simplify whatever you do), maybe there's a "difference of si's" identity you could use? Maybe the difference could be expressed usefully as a differential approximation, or even a full blown Taylor series. Or, maybe there's another way to simplify the infinite sum...
 
Ok, since you are bumping, do you really need to work out the Fourier series to figure out where it converges? Don't you have theorems about where it converges to save you this pain?
 
Dick said:
Ok, since you are bumping, do you really need to work out the Fourier series to figure out where it converges? Don't you have theorems about where it converges to save you this pain?

Haha, I don't know if I mentioned, but this is from a PDE course, and we are asked to compute the Fourier series and see if it converges with the original function...The course doesn't assume a huge background in math except some knowledge in ODE's, linear algebra and multi-calc. Unfortunately I have no more memory of how to do taylor or power series, but I am sure that the question does not ask for that.

Also I did not know about the Si function until I put it in an integrator..I admit that the professor usually goes crazy when coming up with his own problems...

anywho the question asks whether it converges or not...so for all I know I could be right in that it does not converge. Can anybody confirm this?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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