Finding height of frictionless roller coaster

AI Thread Summary
The discussion revolves around calculating the height of a frictionless roller coaster starting point A above the bottom of the loop B. The initial attempt at solving the problem incorrectly defined the reference point, leading to a miscalculation of height as 7.5m. After clarification, it was determined that the correct height should be calculated with respect to point B, resulting in a final answer of 37.5m. The mistake stemmed from using point C as the reference point instead of point B. Properly applying the conservation of energy principles clarified the solution.
Agent M27
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Homework Statement


Consider a frictionless roller coaster. The acceleration due to gravity is 9.8 ms-2. Passenger cars start at point A with zero initial speed, accelerate as they go down to a point B, swing around the vertical circular loop B-C-B of radius 15m, then go on towards further adventures. When a car goes through the top of the loop, point C, the passengers feel weightless. What is the height of the starting point A above the loops bottom, point B?


Homework Equations



Ugi+KEi=Ugf+KEf

mghi+.5mvi2=mghf+.5mv2f

v\geq\sqrt{gr}

The Attempt at a Solution



Since the cart is at the top of the track and has zero initial speed the initial K.E. is canceled out. Also since the final location of the cart is the refrence point, the Ugf will be canceled out, so I am left with the following relationship:

mgh=.5mv2

V= 12.1244 m/s

h=\frac{v<sup>2</sup>}{2g}
=7.5m

This answer is clearly incorrect because the radius of the loop alone is 15m. Any clues as to where I am missing the mark? Thanks in advance.

Joe
 
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Hello Joe,

Agent M27 said:
=7.5m

This answer is clearly incorrect because the radius of the loop alone is 15m.

Not necessarily incorrect. :smile: How did you define your variable 'h'? Take a closer look at how you set up your equations (which might be just fine the way they are, btw. [Although you left out the centripetal force part, but is how I assume you arrived at "v = 12.1244 m/s".]). Did you define 'h' with respect to the ground, or with respect to some other point? :cool:
 
I thought I defined h with respect to the ground, which is why I assumed the final gravitational potential to equal 0. I also made the assumption my starting point had to be higher than the loop just based on intuition, but apparently it doesn't have to be? By the way you worded your reply I am thinking that maybe I found the distance between point C (the top of the loop) and the starting point, is that correct? Thanks again.

Joe
 
Solved it, 37.5m! The issue was that I some how defined my reference point as point C... How did I make that mistake, which assumption was incorrect? Thanks again collinsmark.

Joe
 
Hello Joe,
Agent M27 said:
Solved it, 37.5m! The issue was that I some how defined my reference point as point C... How did I make that mistake, which assumption was incorrect? Thanks again collinsmark.
The only incorrect assumption was your:
mgh=.5mv2
That defines 'h' as the distance from point A to point C (point C is where v is being measured).

If you wanted to define 'h' as the height with respect to point B, the bottom of the loop, the equation should be,

(Potential energy at point A) = (kinetic energy at point C) + (potential energy at point C)
which is,

mgh = 0.5mv2 + mg(30 m)
 
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