- #1

939

- 111

- 2

## Homework Statement

Find the equations of the asymptotes.

## Homework Equations

y = 5x^3 - 4x^2 + 11 / 2x (x^2 - 9)

( 5x^3 - 4x^2 + 11 is the numerator, 2x (x^2 - 9) is the denominator)

## The Attempt at a Solution

Vertical: x = 0, x = -3, x = 3

Horizontal:

**Quick question**...

The degree of the numerator for the first coefficient of the numerator is 3, for first of the denominator it is 1, correct? Thus there is no horizontal asymptote?

OR

Is the degree of the denominator 3, because of 2x and then x^2, in which case it would be 5/2?