Finding how much a 5 cm pad compresses when an egg hits it

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A 56.0 g egg falls 120.0 m and compresses a 5.00 cm foam pad upon impact, taking 6.25 ms to stop. The discussion focuses on calculating the pad's compression using conservation of energy and the egg's speed at impact. Participants clarify the importance of consistent values in the problem statement, particularly the fall distance. The upward acceleration from the foam pad is not needed for the calculation, as the deceleration time is provided. The conversation emphasizes the need for accurate data to solve the problem effectively.
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Homework Statement


A 56.0 g egg falls 120.0 m from rest and hits a 5.00 cm thick foam pad. The egg does not break, but instead compresses the foam pad. It is 6.25 ms from the moment the egg hits the foam ad until all downward motion (falling) is stopped. Assuming there is a constant upward acceleration due to the compressing of the foam pad, how much is the pad compressed?

m= 56.0 g; delta y= 12 m; pad= 5.00 cm; delta t= 6.25 ms; a= -9.81 m/s2


Homework Equations



m1v1,i+m2v2,i=m1v1,f + m2v2,f; KE= 1/2mv2; F(delta t)= delta P

I really have no idea what to do in this case, and I need to get this equation done. It's the last one on my set. Please help!
 
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You could try using conservation of energy to get the speed of the egg at the moment of impact and then use that to get the acceleration of the egg.
 
You just made my life so much easier! Thank you!
 
MelloDramatic said:
You just made my life so much easier! Thank you!
Are you sure that your problem statement contains all the relevant information? Perhaps the value of the upward acceleration due to the foam pad is missing?
 
gneill said:
Are you sure that your problem statement contains all the relevant information? Perhaps the value of the upward acceleration due to the foam pad is missing?

Nope. This information is not required. Here's a hint: the deceleration time is given, and a constant force is assumed. :wink:

To the original poster: is it 120.0 m or 12 m? You've written both of these in two different places. The latter gives me an answer that works. The former does not (i.e. the pad will not be thick enough).
 
cepheid said:
Nope. This information is not required. Here's a hint: the deceleration time is given, and a constant force is assumed. :wink:

Ah yes. How late-night-fuzzy-headed of me. Thanks.
 
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