Finding inverse functions when there is X^2+x

In summary, the conversation is about solving for x in the equation x^2 + 2x = y, which is a simple quadratic equation. The process involves adding 1 to both sides to create a perfect square, taking the square root, and using the ± symbol to account for both possible solutions. However, it is noted that this equation does not have an inverse function unless the domain is restricted.
  • #1
applestrudle
64
0

Homework Statement



f(x)= 2x + x^2

Homework Equations





The Attempt at a Solution



I don't know how to make x the subject
 
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  • #2
applestrudle said:

Homework Statement



f(x)= 2x + x^2

Homework Equations





The Attempt at a Solution



I don't know how to make x the subject

You need to solve for x in the equation x^2 + 2x = y. This is a simple quadratic equation.
 
  • #3
Ray Vickson said:
You need to solve for x in the equation x^2 + 2x = y. This is a simple quadratic equation.

Okay thank you!

I've got it:

X^2 +2x = y

add one so you get a quadratic that has a "squared"

x^2 +2x +1 = y + 1

solve quadratic:

(x+1)^2 = y + 1

x = (y+1)^-1/2 -1

f-1(x) = (x+1)^-1/2 -1

:)
 
Last edited:
  • #4
applestrudle said:
Okay thank you!

I've got it:

X^2 +2x = y

add one so you get a quadratic that has a "squared"

x^2 +2x +1 = y + 1

solve quadratic:

(x+1)^2 = y + 1

x = (y+1)^-1/2 -1
No.
Starting from two lines above, you want to solve for x.
When you do this, don't forget that you need ± in there somewhere.
applestrudle said:
f-1(x) = (x+1)^-1/2 -1

:)
Note that the equation y = x2 + 2x does not give y as a 1-to-1 function of x, so there is no inverse function, unless you place restrictions on the domain.
 
  • #5
applestrudle said:
f-1(x) = (x+1)^-1/2 -1

:)
You have raised to the power -1/2. Where did the negative sign come from?
 
  • #6
oay said:
You have raised to the power -1/2. Where did the negative sign come from?

Sorry, mistake when I was typing! Thank you for pointing it out
 

1. How do I find the inverse function when there is an x^2+x term?

To find the inverse function of a function with an x^2+x term, you can use the following steps:

  1. Write the original function in the form of y = f(x).
  2. Replace y with x and x with y to create the inverse function in the form of x = f(y).
  3. Solve for y in terms of x.
  4. Replace y with f-1(x) to get the final inverse function.

2. Can I use the quadratic formula to find the inverse function of x^2+x?

No, you cannot use the quadratic formula to find the inverse function of x^2+x. The quadratic formula is used to solve for x in a quadratic equation, not to find inverse functions. You can use the steps outlined in question 1 to find the inverse function of x^2+x.

3. Is the inverse function of x^2+x always a one-to-one function?

Yes, the inverse function of x^2+x is always a one-to-one function. This is because the original function has a unique output for every input, and the inverse function simply switches the input and output values. Therefore, it also has a unique output for every input, making it a one-to-one function.

4. How can I graph the inverse function of x^2+x?

To graph the inverse function of x^2+x, you can use the following steps:

  1. Graph the original function y = x^2+x.
  2. Draw the line y = x on the same graph.
  3. The point where these two lines intersect will be the point (a, a), where a is the input value for the inverse function.
  4. Plot this point on the graph and draw a line through it with a slope of -1.
  5. This line is the graph of the inverse function.

5. Can I use a calculator to find the inverse function of x^2+x?

While some calculators have the ability to find inverse functions, they may not work for all functions, including x^2+x. It is best to use the steps outlined in question 1 to find the inverse function of x^2+x manually.

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