Finding Inverse of f(x)=3x+5/x-4

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Homework Help Overview

The discussion revolves around finding the inverse of the function f(x) = (3x + 5)/(x - 4). Participants are exploring the algebraic manipulation required to isolate y in terms of x.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss switching x and y to begin finding the inverse. There are various attempts to manipulate the equation, including multiplying both sides by (y - 4) and rearranging terms. Some participants express confusion about handling variables and the steps to isolate y.

Discussion Status

There is an ongoing exploration of different algebraic approaches to solving for y. Some participants provide corrections and alternative methods, while others express understanding as the discussion progresses. No explicit consensus is reached, but guidance is offered on how to factor and rearrange the equation.

Contextual Notes

Participants note the importance of proper notation and parentheses in the function definition, which affects the interpretation of the problem. There is also mention of a negative sign that was initially overlooked in the equation.

bael
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Homework Statement


find a formula for f-1 when f is defined by
f(x) = 3x+5/x-4


Homework Equations





The Attempt at a Solution


Here is what I've done so far:
First I switch the x and the y so I get
x=3y+5/y-4
x(y-4)=3y+5
xy-4x=3y+5
xy=3y+4x+5
xy-3y=4x+5
y-3y=4x+5/x
-2y=4+5
I don't know what else to do. No matter what I try I always end up deleting a variable.
 
Last edited:
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Okay so first you switch the x's and y's.
Then you'll have:

x= (3y+5)/(y-4)

Let's multiply by y-4

which leaves... xy-4x = 3y+5

when you want to solve for a variable and there's two of them, you want to get them on the same side and factor it out.

so now what you do is subtract 5, (move it to the left) and move the subtract xy (move to right)

so you end up with

5-4x = 3y-xy

now let's factor out y

5-4x = y(3-x)

now we divide by (3-x)

your final answer is (5-4x)/(3-x) = y
 
*sorry I forgot to put the negative sign on 5...it should be (-5-4x)/(3-x) = y
 
@bael: First off, put in parentheses next time. What you wrote looks like this:
f(x) = 3x+\frac{5}{x}-4
bael said:
Here is what I've done so far:
First I switch the x and the y so I get
x=3y+5/y-4
x(y-4)=3y+5
xy-4x=3y+5
xy=3y+4x+5
xy-3y=4x+5
y-3y=4x+5/x
-2y=4+5
I don't know what else to do. No matter what I try I always end up deleting a variable.

The bolded is where your problem lies. You can't divide both sides by x like that. If you were to divide both sides by x, this would have been the result:
xy-3y=4x+5
\frac{xy-3y}{x}=\frac{4x+5}{x}
\frac{xy}{x}-\frac{3y}{x}=\frac{4x}{x}+\frac{5}{x}
y-\frac{3y}{x}=4+\frac{5}{x}
This is not the way to go.

What theclock54 posted isn't wrong (now that the correction was made), but from this step:
xy-4x = 3y+5

... I would instead add 4x to both sides and subtract 3y from both sides. I prefer to have the x terms before the constant terms in the numerator & denominator.
xy - 3y = 4x + 5

Then factor out the y, and divide both sides by (x - 3):
y(x - 3) = 4x + 5
y = \frac{4x + 5}{x - 3}
 
Thanks a lot, I understand it now.
 

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