Finding Laurent Series for a Rational Function on an Annulus

QuantumLuck
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Homework Statement


find the Laurent series for f(z) = 1/(z(z-1)(z-2)) on the annulus between 1 and 2. with the origin as center.


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The Attempt at a Solution


so i found the partial fraction decomposition of this function and it turns out to be f(z) = 1/2z + -1/(z-1) + 1/(2(z-2)). In order to find the Laurent series do I just Taylor expand each of my 3 different decomposition around their singularities? However, their singularities are not contained on the annulus so this doesn't seem to make much sense. I am unsure how to proceed from this spot.
 
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Note that 1/2z and -1/(z-1) have their singularity "inside" the annulus, while 1/(2(z-2)) has a singularity "outside" the annulus. Try expressing the first two as series in 1/z and the third one as a series in z (i.e. Taylor series).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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