Finding length of a complex number

AI Thread Summary
The discussion focuses on calculating the modulus of a complex number defined as \widehat C = \frac{1-\widehat a}{1+\widehat a}\widehat B. The formula for the modulus is confirmed to be |\widehat C| = \frac{|1-\widehat a|}{|1+\widehat a|}|\widehat B|. A caution is provided regarding the calculation of |1-\widehat{a}|, which involves the expression \sqrt{(1-\alpha)^2 + \beta^2} when \widehat{a} is expressed as \alpha + i\beta. The importance of careful computation in complex number modulus is emphasized. Understanding these calculations is essential for accurate results in complex number analysis.
Niles
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Homework Statement


Hi all.

Please take a look at this complex number:

<br /> \widehat C = \frac{1-\widehat a}{1+\widehat a}\widehat B,<br />

where a hat indicates that the number is complex. Can you confirm me in that the length (modulus) of this complex number |\widehat C| is given by:

<br /> |\widehat C| = \frac{|1-\widehat a|}{|1+\widehat a|}|\widehat B|<br />

Thanks in advance.Niles.
 
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Niles said:

Homework Statement


Hi all.

Please take a look at this complex number:

<br /> \widehat C = \frac{1-\widehat a}{1+\widehat a}\widehat B,<br />

where a hat indicates that the number is complex. Can you confirm me in that the length (modulus) of this complex number |\widehat C| is given by:

<br /> |\widehat C| = \frac{|1-\widehat a|}{|1+\widehat a|}|\widehat B|<br />

Thanks in advance.Niles.
Yes, but you need to be careful. Note that if \widehat{a} = \alpha + i\beta then

\left|1-\widehat{a}\right| = \sqrt{\left(1-\alpha\right)^2 + \beta^2}
 
Thanks a lot for responding quickly.
 
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