- #1

PenDraconis

- 11

- 0

## Homework Statement

Tell whether following systems are i. linear and ii. time-invariant:

$$y(t) = \int_{-\infty}^t x(\tau)d\tau$$

$$y(t) = \int_{0}^t x(\tau)d\tau$$

$$y(t) = \int_{t-1}^{t+1} x(\tau)d\tau$$

$$y(t) = \int_{0}^t x(\tau)d\tau$$

$$y(t) = \int_{t-1}^{t+1} x(\tau)d\tau$$

## Homework Equations

N/A

## The Attempt at a Solution

I'm a little thrown off by the integrals but here's my best explanation, all 3 of them are linear, why? Because the constants can be pulled out of the integrals thus fulfilling the scaling property that y(t) = x(t) and Cy(x) = C(x); similarly the concept of an integral inherently proves the additive property necessary for linearity.

As for time-invariance, I'm also inclined to say all of them are time-invarient, why? If we take a look at the systems ( once they've already been integrated we can see this - example of the first integral):

$$y(t) = C(x_{integrated}(t) - x_{integrated}(-\infty))$$

It seems to me that this clearly shows that if you delay t by 1 your output will also be delayed by one.

Let me know if I have any errors in my thought process or how I went about this, LTI systems are still a little difficult for me to "reason" through, although I am very comfortable with what they stand for the analysis is just...magic.