Finding m for Solution of Differential Equation y = e^{mx}

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SUMMARY

The values of m that satisfy the differential equation 5y' = 2y for the function y = e^{mx} are determined to be m = 2/5. The solution process involves differentiating y to obtain y' = me^{mx}, leading to the equation 2e^{mx} = 5me^{mx}. By simplifying this equation, it is established that 2 = 5m, confirming that m = 2/5 is the correct solution. Verification of this result can be performed by substituting m back into the original differential equation.

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Homework Statement



Find the values of m so that the function [tex]y = e^{mx}[/tex] is a solution of the given differential equation.

Homework Equations



[tex]y = e^{mx}[/tex]
[tex]5y^{'} = 2y[/tex]

The Attempt at a Solution



I am not sure if this is right:

[tex]y^{'} = me^{mx}[/tex]

[tex]5y^{'} = 5me^{mx}[/tex]
[tex]2y = 2e^{mx}[/tex]

[tex]2e^{mx} = 5me^{mx}[/tex]

[tex]2 = 5m[/tex]

[tex]m = 2/5[/tex]
 
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Check it and see. You've already done all the hard work, and checking is a simple matter of seeing whether y = e2x/5 satisfies your differential equation.
 
Ok, Thank you.
 

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