Finding magnetic force on two different segments

AI Thread Summary
To calculate the magnetic force on the semicircular current loop segments, the formula F = I(L X B) can be applied, where L represents the length of the wire. The discussion highlights the importance of using the right-hand rule (RHR) to determine the direction of the forces acting on the segments. The magnitude of the force can also be expressed as |F| = ILBsin(θ). An alternative formula, F = (μ₀ I₁ I₂ L) / (2πr), is suggested for calculating the force between current-carrying wires. Understanding these formulas and their applications is crucial for solving the problem effectively.
ultrabionic_ang
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I've been having some trouble with this homework problem:

There is a semicircular current loop that lies in the xy plane. The straight segment "a" of of the loop has length 2R while the semicircular segment "b" has radius R. There is a magnetic field of strength B into the page. Current I is flowing counterclockwise. How would the magnetic force on segments a and b and net force be calcuated? Is it just simply using

F = I(L X B), L being the length of the wire
 
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ultrabionic_ang said:
I've been having some trouble with this homework problem:

There is a semicircular current loop that lies in the xy plane. The straight segment "a" of of the loop has length 2R while the semicircular segment "b" has radius R. There is a magnetic field of strength B into the page. Current I is flowing counterclockwise. How would the magnetic force on segments a and b and net force be calcuated? Is it just simply using

F = I(L X B), L being the length of the wire

Kid, we are talking about circuits... This is the part where pictures do mean a thousand words. Let's talk about RHR first and find the direction of forces...

The magnitude of F is such that: |F| = ILBsin@

I would somewhat agree using this forumla... Looking at this... I see you've got currents and it makes me want to use this formula:

F = U_o I_1 I_2 L / 2 \Pi r

I prefer this, and I think this is what we use.
 
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