Finding Magnitude & Angle of Vector A (4.0m, -3.0m)

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To find the magnitude of vector A = (4.0m)i + (-3.0m)j, the Pythagorean theorem is applicable, yielding a magnitude of 5.0 meters. For the angle relative to the i-axis, the tangent function can be used, specifically calculating the arctangent of the ratio of the j-component to the i-component. This discussion emphasizes the importance of understanding vector components and their conversion between rectangular and polar forms. Resources like Wikipedia can provide additional guidance on this topic. Mastering these concepts is essential for effectively working with vectors in physics.
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Problem: The vector A = (4.0meters)i + (-3.0meters)j
Find a) its magnitude and b) its angle in relation to i.

Question: I know magnitude is a scalar but don't know what I am really trying to find in this problem. Am I looking for the direct point from the start of i to the end of j? Do I just need to use the pythagoream therom to find the magnitude.
To find its angle do I just need to use tangent?
 
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dakar76 said:
Problem: The vector A = (4.0meters)i + (-3.0meters)j
Find a) its magnitude and b) its angle in relation to i.

Question: I know magnitude is a scalar but don't know what I am really trying to find in this problem. Am I looking for the direct point from the start of i to the end of j? Do I just need to use the pythagoream therom to find the magnitude.
To find its angle do I just need to use tangent?

Welcome to the PF. Yes on Pythagoream theorem for magnitude. What trig function can you use to find the angle?

If you still have problems, just go to wikipedia and look for info on converting vectors between rectangular and polar forms.
 
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