Mathematica Finding Minimum Value with Mathematica

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To find the minimum value of ∂ω2 using Mathematica, the function can be simplified to E^(2 gamma[t]) Csc[delta t]^2 - Cot[delta t]^2, assuming n and T are positive constants. The behavior of Csc^2 and Cot^2 at multiples of Pi indicates that the function approaches infinity at those points. The sign of n and T affects the overall function's orientation, but since they are positive integers, they can be ignored in the analysis of minima. If E^(2 gamma[t]) is less than 1 when delta t equals Pi, the minimum value of the function could potentially be negative infinity. The discussion emphasizes the importance of understanding the function's behavior near critical points to determine the minimum.
aredy29
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∂ω2 = (1-cos2(Δt)e-2γ(t))/(nTtsin2(Δt)e-2γ(t))

n,T are assumed as constants. How can I use Mathematica to find the values of Δ and t that will give the minimum values for ∂ω2 ?
 
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If I use Expand on your function I get

1/(n T t)((E^(2 gamma[t]) Csc[delta t]^2 - Cot[delta t]^2)

Without knowing the signs of n and T we can't know the sign of the result and can't know minimum.

Both Csc^2 and Cot^2 go to infinity at multiples of Pi. Depending on what your gamma function is, either the term with Csc or Cot will win the race to infinity and I believe you can determine the minimum by inspection.
 
What do you mean with sign of n and T ?
 
aredy29 said:
What do you mean with sign of n and T ?

If n*T is negative the whole function will be flipped upside down, what was a minimum would be a maximum, etc.
 
n and T are integers and always positive.
 
aredy29 said:
n and T are integers and always positive.

Then I believe, if you can verify the result from Expand, that n and T can be ignored and you focus on

E^(2 gamma[t]) Csc[delta t]^2 - Cot[delta t]^2

If E^(2 gamma[t]) can be < 1 when delta t=Pi then the minimum appears to be -Infinity.
 

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