Finding N(T) and R(T): Solving a Linear Transformation Problem

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Alright this problem has really gotten me confused. I skipped 1 and 2 because I know how to do those, but 3 and 4, I do not.

I think the problem statement is saying the linear transformation transforms the vector space V to R^2. and it's defined by T(f)=...

For 3) find a basis for N(T)

The book defines N(T) as = {v ε V l T(v)=0}
So I must find T such that T(v)=0.


I have no clue how to do this problem. can someone give me a hint?
I've looked at other types of problems where we find a basis for N(T) and those seem easy, but this one just got me confused.

What is f?
 
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pyroknife said:
Alright this problem has really gotten me confused. I skipped 1 and 2 because I know how to do those, but 3 and 4, I do not.

I think the problem statement is saying the linear transformation transforms the vector space V to R^2. and it's defined by T(f)=...

For 3) find a basis for N(T)

The book defines N(T) as = {v ε V l T(v)=0}
So I must find T such that T(v)=0.

I have no clue how to do this problem. can someone give me a hint?
I've looked at other types of problems where we find a basis for N(T) and those seem easy, but this one just got me confused.

What is f?
Where are the problems?

I see none !

Added in Edit:

Here it is:

attachment.php?attachmentid=52421&d=1351485538.png
 
Last edited:
SammyS said:
Where are the problems?

I see none !

SammyS said:
Where are the problems?

I see none !

Oh sorry.
 

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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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