Finding Net Force [w/ Vector Addition]

AI Thread Summary
To find the net force acting on a 20 kg object influenced by three forces, vector components must be added. The calculated components resulted in 80.64 N [E] and 19.78 N [N]. Using the Pythagorean theorem, the resultant vector was found to be 83.03 N [E3.5N]. It is essential to include the direction of the resultant force, as acceleration is a vector quantity that aligns with the net force's direction. Understanding this relationship is crucial for accurately determining the object's acceleration.
harujina
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Homework Statement



A 20 kg object is being acted on by a 90 N [E60N] force, a 40 N force, and a 40 N [E27S] force.
Find the net force acting on the object and its acceleration.

Homework Equations



ƩF = ma

The Attempt at a Solution



I understand that I have to add vector components here.
So as a result, I got 80.64 N [E] and 19.78 N [N].
I got a force pulling North and a force pushing East. But now I don't know what to do with these forces...?
 
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Assuming you worked correctly so far, these are the components of the resultant force.
You need to find the magnitude and the direction (angle) of this resultant.
 
harujina said:

Homework Statement



A 20 kg object is being acted on by a 90 N [E60N] force, a 40 N force, and a 40 N [E27S] force.
Find the net force acting on the object and its acceleration.

Homework Equations



ƩF = ma

The Attempt at a Solution



I understand that I have to add vector components here.
So as a result, I got 80.64 N [E] and 19.78 N [N].
I got a force pulling North and a force pushing East. But now I don't know what to do with these forces...?


Well, what force vector did you get when you added the components of the original three vectors which were given? Don't you get a Resultant vector with a magnitude and a direction?

Can't you use this resultant vector to answer the second part of your problem?
 
Oh, so is it right for me to use Pythagorean theorem here to find the resultant vector?
and then that would be the net force which can be used to determine acceleration, correct?

*I worked it out and got 83.03 N [E3.5N]
Just wondering if it's necessary to include direction [E3.5N]
I know acceleration is a vector quantity but what does this implicate? Simply the direction of acceleration for my final answer?
 
harujina said:
Oh, so is it right for me to use Pythagorean theorem here to find the resultant vector?
and then that would be the net force which can be used to determine acceleration, correct?

*I worked it out and got 83.03 N [E3.5N]
Just wondering if it's necessary to include direction [E3.5N]
I know acceleration is a vector quantity but what does this implicate? Simply the direction of acceleration for my final answer?
Yes, the direction of the acceleration is always in the direction of the net force.
 
PhanthomJay said:
Yes, the direction of the acceleration is always in the direction of the net force.

Ok, thank you!
 
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