Finding Partial Derivatives with Independent Variables

justwild
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Homework Statement


A function f(x,t) depends on position x and time t independent variables. And if \dot{f} represents \frac{df(x,t)}{dt} and \dot{x} represents \frac{dx}{dt}, then find the value of \frac{\partial\dot{f}}{\partial\dot{x}}.

Homework Equations




The Attempt at a Solution



Using the formula for total differential I can have
\dot{f} = f_{x}\dot{x} + f_{t}
Now when I proceed with differentiating partially the above equation wrt \dot{x} I am struck.
 
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justwild said:

Homework Statement


A function f(x,t) depends on position x and time t independent variables. And if \dot{f} represents \frac{df(x,t)}{dt} and \dot{x} represents \frac{dx}{dt}, then find the value of \frac{\partial\dot{f}}{\partial\dot{x}}.

Homework Equations




The Attempt at a Solution



Using the formula for total differential I can have
\dot{f} = f_{x}\dot{x} + f_{t}
Now when I proceed with differentiating partially the above equation wrt \dot{x} I am struck.

Well, ##f(x,t)## doesn't depend on ##\dot x##, so ##f_x## and ##f_t## don't depend on ##\dot x## either.
 
Dick said:
Well, ##f(x,t)## doesn't depend on ##\dot x##, so ##f_x## and ##f_t## don't depend on ##\dot x## either.

So, I will get the answer as ##f_x##. It's right.

But I didn't understand why. Can you give me a reference? I would like to read more on this.
 
justwild said:
So, I will get the answer as ##f_x##. It's right.

But I didn't understand why. Can you give me a reference? I would like to read more on this.

Why do you say it is right? Is somebody telling you that?
 
justwild said:
So, I will get the answer as ##f_x##. It's right.

But I didn't understand why. Can you give me a reference? I would like to read more on this.

You could look up Euler-Lagrange equations or Calculus of Variations, but the idea here is to just treat ##x## and ##\dot x## as independent variables.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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