Finding Planetary Radius using density and escape velocity

AI Thread Summary
To calculate the radius of a planet with a mean density of 3.0x10^3 kg/m³ and an escape velocity of 40 m/s, the relevant equations involve gravitational principles and the relationship between mass, density, and volume. The escape velocity equation, Vesc = √(2GM/r), can be rearranged to find radius, but requires the planet's mass, which is derived from its density and volume. The volume of a sphere is V = (4/3)πr³, leading to the mass equation M = ρV. The discussion highlights confusion over algebraic rearrangements and the need for clarity in deriving the mass from density, emphasizing the importance of careful calculations and unit consistency.
elDuderino81
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1. "Calculate the radius of a planet with mean density of 3.0x10^3 m2kg-3, from which a golf ball can be thrown to infinity as a velocity of 40 ms-1"


Homework Equations


I've been looking at the equation of:

Vesc=sqroot of 2*G*M/r and rearranging to r=2*G*M/Vesc. However, the trouble is, I'm struggling to get the mass from the density? It appears I don't have enough information, or I'm barking up the wrong tree so to speak?


The Attempt at a Solution



can anyone point me in the right direction please?
 
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elDuderino81 said:
1. "Calculate the radius of a planet with mean density of 3.0x10^3 m2kg-3, from which a golf ball can be thrown to infinity as a velocity of 40 ms-1"

Homework Equations


I've been looking at the equation of:
fra
Vesc=sqroot of 2*G*M/r and rearranging to r=2*G*M/Vesc.


Recheck your algebra there. What happened to the square root?

However, the trouble is, I'm struggling to get the mass from the density? It appears I don't have enough information, or I'm barking up the wrong tree so to speak?

The Attempt at a Solution



can anyone point me in the right direction please?

Start with the conservation of energy statement ##\frac{1}{2}mv_e^2 = \frac{GMm}{r}## that leads to the equation you started with. ##m## is the mass of the golf ball (cancels out), while ##M## is the mass of the planet.

Now find an expression for ##M## in terms of the density and the radius. Assume the planet is a spherical ball of radius ##r##. What's the enclosed volume of a perfect sphere?
 
Curious3141 said:
Recheck your algebra there. What happened to the square root?
Start with the conservation of energy statement ##\frac{1}{2}mv_e^2 = \frac{GMm}{r}## that leads to the equation you started with. ##m## is the mass of the golf ball (cancels out), while ##M## is the mass of the planet.

Now find an expression for ##M## in terms of the density and the radius. Assume the planet is a spherical ball of radius ##r##. What's the enclosed volume of a perfect sphere?

The enclosed volume of a perfect sphere is is V=(3/4)∏*r3, and when rearranging the previous equation I get r=GM/0.5Ve^2 and M=G/0.5V^2*r?

I'm still struggling to see what I can do with this, as it appears that to find r I need M and to find M I need r? I'm really confused :-(
 
Last edited:
elDuderino81 said:
The enclosed volume of a perfect sphere is is V=(3/4)∏*r3, and when rearranging the previous equation I get r=GM/0.5Ve^2 and M=G/0.5V^2*r?

I'm still struggling to see what I can do with this, as it appears that to find r I need M and to find M I need r? I'm really confused :-(

You have ##V##. What's the relationship between mass, density and volume? Hence what is ##M## in terms of ##r##?

Replace ##M## with that expression. Rearrange to isolate ##r## on one side of the equation. That's just simple algebra. But be careful with it - you seem prone to making mistakes with this. The expressions you wrote are ambiguous (you should use LaTex formatting), but there seems to be mistake with the rearrangement here too.
 
elDuderino81 said:
The enclosed volume of a perfect sphere is is V=(3/4)∏*r3, ... I'm really confused :-(

Yes, you are confused.

Is your planet a flabby sphere? You should recheck your formula for the volume of a sphere. I also didn't understand the units of average density in the OP for the planet. The units of density are ML^-3.
 
SteamKing said:
Yes, you are confused.

Is your planet a flabby sphere? You should recheck your formula for the volume of a sphere. I also didn't understand the units of average density in the OP for the planet. The units of density are ML^-3.

Hi, sorry about the typo, i should have wrote (4/3)∏r^3

In regards to units of density, again that was a typo and should read 3*10^3 kg M^-3, which is what has been provided in the problem set.
 
elDuderino81 said:
Hi, sorry about the typo, i should have wrote (4/3)∏r^3

In regards to units of density, again that was a typo and should read 3*10^3 kg M^-3, which is what has been provided in the problem set.

OK, so what's ##M##, as I asked in my post? You may represent the density by ##\rho##.
 
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