1. The problem statement, all variables and given/known data At what point on the curve y=2(x-cosx) is the tangent parallel to the line 3x-y=5. 3. The attempt at a solution 1. rewrite 3x-y=5 as y-3x-5 2. equate 2(x-cosx) = y-3x-5 3. differentiate: 2+2sinx = 3 4. solve for x: sin^-1(,5) = 0.524 5. plug into y=2(x-cosx) to get y value: y = -0.684 I am not sure I have this correct though. At stage 4 above, I have a trig equation. So doesn't that give me an infinite number of solutions. (I was not given a range in this question). Or do I just look at the graph of 2(x-cosx) and y-3x-5 to see logically where the point of equal slope is ? Thanks for any help.