(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

At what point on the curve y=2(x-cosx) is the tangent parallel to the line 3x-y=5.

3. The attempt at a solution

1. rewrite 3x-y=5 as y-3x-5

2. equate 2(x-cosx) = y-3x-5

3. differentiate: 2+2sinx = 3

4. solve for x: sin^-1(,5) = 0.524

5. plug into y=2(x-cosx) to get y value: y = -0.684

I am not sure I have this correct though. At stage 4 above, I have a trig equation. So doesn't that give me an infinite number of solutions. (I was not given a range in this question). Or do I just look at the graph of 2(x-cosx) and y-3x-5 to see logically where the point of equal slope is ?

Thanks for any help.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Finding point where slope of line equals curve

**Physics Forums | Science Articles, Homework Help, Discussion**