Finding Potential Energy of a Particle in a Region of Space

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To find the potential energy U(x) of a particle with the given wave function and energy, one should use the time-independent Schrödinger equation. The equation is formulated as -\frac{\hbar^2}{2m}\frac{d^2}{dx^2} \psi(x) + U(x) \psi(x) = E \psi(x). By substituting the known wave function and energy into this equation, the second derivative of the wave function must be calculated. This process will yield the potential energy function U(x). The discussion clarifies the approach to solving for U(x) using the correct wave equation.
Tony11235
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In a region of space, a particle has a wave function given by \psi(x) = A\exp(\frac{-x^2}{2L^2}}) and energy E = \frac{\hbar^2}{2mL^2}

Find the potential energy as a function of x.

Do I plug these into the time independent wave equation and solve for U(x) ? If so, I don't see what exactly I'm supposed to do with the energy, E. There is already a similar term in the wave equation.
 
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Tony11235 said:
In a region of space, a particle has a wave function given by \psi(x) = A\exp(\frac{-x^2}{2L^2}}) and energy E = \frac{\hbar^2}{2mL^2}

Find the potential energy as a function of x.

Do I plug these into the time independent wave equation and solve for U(x) ? If so, I don't see what exactly I'm supposed to do with the energy, E. There is already a similar term in the wave equation.

-\frac{\hbar^2}{2m}\frac{d^2}{dx^2} \psi(x) + U(x) \psi (x) = E \psi(x).
Plug in what you know, take the derivative and solve for U(x).

-Dan
 
Ok I was thinking of the time-dependent wave equation.
 
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