Finding rafts velocity relative to the water using 2 masses and one velocity

AI Thread Summary
A 50 kg person walking at 2 m/s across a 250 kg raft results in a calculation for the raft's velocity relative to the water. Using conservation of momentum, the equation mv + MV = 0 leads to the derived formula v = 2M/(m+M). Substituting the given masses, the velocity of the raft is calculated to be -0.33 m/s, indicating it moves in the opposite direction to the person's movement. The solution confirms that the calculations are correct. The answer is validated as accurate within the context of the problem.
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Homework Statement


A 50 kg person walks across a 250 kg raft at a constant speed of 2m/s. What is the velocity of the raft relative to the water?


Homework Equations





The Attempt at a Solution


Let m = mass of the person
M = mass of the raft
v = velocity of the person relative to the water
V = velocity of the raft relative to the water
v=V+2 so V=v-2

mv + MV = 0
mv + M(v-2) = 0
mv + Mv - 2M = 0
(m+M)v - 2M = 0
(m+M)v = 2M
v= 2M/(m+M)

v= 2(250)/(50+250)
v= 500/300
v= 1.67 m/s

V= v-2
V= 1.67 - 2
V= -.33 m/s
Ans: -.33 m/s
 
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Your answer is right according to me.
Whats the problem?
 
I just wanted to make sure the answer was correct
 
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