Finding resultant at each pair of forces

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The discussion focuses on calculating the resultant of two forces: 6 N southwest and 8 N northwest. The resultant is determined to be 10 N at an angle of N82°W. Participants express difficulty in visualizing the vectors and understanding the angle calculation. There is a suggestion to provide a sketch of the vectors to clarify the process. Additionally, the importance of converting between rectangular and polar forms of vectors is highlighted for better comprehension.
ssb1
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Find the resultant of each pair of forces acting on an object

Q: forces of 6 N southwest and 8 N northwest

I got 10 for the resultant, but how do I find the angle?

The answer is apparently is 10 N, N82degW

Having a hard time visualizing this...
 
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ssb1 said:
Find the resultant of each pair of forces acting on an object

Q: forces of 6 N southwest and 8 N northwest

I got 10 for the resultant, but how do I find the angle?

The answer is apparently is 10 N, N82degW

Having a hard time visualizing this...

Welcome to the PF.

(next time you start a schoolwork thread, please do not delete the Homework Help Template -- please fill it out instead) :smile:

Can you post a sketch of the two vectors, and show how you got the magnitude of the sum? Show the angles as well.

Are you familiar with converting between rectangular and polar forms of vectors?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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