Finding Roots of Diff EQ: c1 & c2?

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In determining the general solution of a homogeneous linear ordinary differential equation, the assignment of constants c1 and c2 to the roots does not affect the solution's validity. The roots can be interchanged without altering the outcome, as both forms yield equivalent solutions. There is no strict convention for naming the roots m1 and m2; it often varies by publisher or context. The key point is that c1 and c2 are arbitrary constants that must be defined by initial conditions. Ultimately, the interchange of constants does not impact the solution's correctness.
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When you are trying to determine the general solution of a homogeneous linear ordinary differential equation, after you find the roots, how do you decide which goes with c1 and which goes with c2?

example:

y''-3y'+2y=0

Factoring the auxiliary equation

m^2-3m+2=0=(m-1)(m-2)

is there some kind of convention as to which gets named as m1 and m2?
It seems like every time I do one of these kinds of problems, my answer is the opposite of the books. Is there any difference between

y=c1e^(x)+c2e^(2x) and y=c1e^(2x)+c2e^(x)?
 
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c1 and c2 are arbitrary constants which must be determined by initial conditions only. so there is no difference if you interchange them
 
That's what I was hoping for, thanks.
 
Is there any difference between

y=c1e^(x)+c2e^(2x) and y=c1e^(2x)+c2e^(x)?
No, they have no different... you can write it either way...

is there some kind of convention as to which gets named as m1 and m2?

It depend on the publisher...
 
kdinser said:
When you are trying to determine the general solution of a homogeneous linear ordinary differential equation, after you find the roots, how do you decide which goes with c1 and which goes with c2?

example:

y''-3y'+2y=0

Factoring the auxiliary equation

m^2-3m+2=0=(m-1)(m-2)

is there some kind of convention as to which gets named as m1 and m2?
It seems like every time I do one of these kinds of problems, my answer is the opposite of the books. Is there any difference between

y=c1e^(x)+c2e^(2x) and y=c1e^(2x)+c2e^(x)?

Read the result from right to left.I'm sure it will coincide with yours...

Daniel.
 
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