Finding the angle of a falling person on a sphere

AI Thread Summary
A skier on top of a sphere with radius R will slide off when the gravitational force component towards the center is less than the required centripetal force. The initial calculations involved energy conservation and centripetal force equations, leading to an angle of 48.2 degrees. However, a misunderstanding arose regarding the role of centripetal force, as the skier's movement is primarily influenced by gravity. After clarification, it was confirmed that the teacher made an error in interpreting the forces involved. The final conclusion is that the calculations for the angle were indeed correct.
Enderless
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Homework Statement



A sphere is on the ground, with the sphere having a radius R. A person (skier) is standing on top of the sphere. neglecting friction, find the angle at which the person will slide off the sphere if he moves from rest to a constant velocity of v.

http://img63.imageshack.us/img63/930/untitledai7.jpg

Homework Equations



F = ma
F = mv^2/r (centripetal force)
U + K = U + K (conservation of energy)


The Attempt at a Solution



1/2mv^2 + mgh = 1/2mv^2 + mgh
0J + m(9.8m/s^2)(2R) = 1/2mv^2 + m(9.8m/s^2)(R + Rcos (angle))

So that simplifies to v^2/2 = 9.8 m/s(R) - 9.8m/s(Rcos (angle))

Drawing a free body diagram, I know that the centripetal force is equal to the Normal foce*cos(angle):

mv^2/r = mgcos(angle)
v^2/r = 9.8m/s (cos (angle)
v^2 = 9.8 m/s (Rcos(angle))

Substitute that into v^2/2 = 9.8 m/s(R) - 9.8m/s(Rcos (angle)) and get:

9.8m/s Rcos (angle)) = 19.6 m/s(R) - 19.6m/s (Rcos (angle))

That reduces to:

cos (angle) = 2/3
so the angle must be 48.2 degrees


My teacher said it was wrong, can anyone assist me?
 
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I a person is sking down a sphere, there is no "centripetal force"- there is no force on the person toward the center of the sphere. The only force is that of gravity, straight down.
 
A centripetal force is included in the problem. I didn't type the whole problem out.
 
The centripetal force is the force towards the center due to gravity and the normal... if the skier is moving along the sphere:

the net force towards the center = mv^2/r

component of gravity towards the center - normal force = mv^2/r

When the component of gravity towards the center becomes less than mv^2/r it is impossible for the skier to move along the sphere... force towards the center at this point cannot be mv^2/r because the normal force can't be negative...
 
I got it now! Turns out my teacher made an error. :smile:

Thanks everyone
 
Enderless said:
I got it now! Turns out my teacher made an error. :smile:

Thanks everyone

Cool. Looking at your solution now, I see it is exactly right.
 
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