Finding the confidence interval

Pietair
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Homework Statement



What formula do I need to find the confidence interval, when I have got:

- Number of samples
- Level of Confidence
- The assumed (1st guess) accuracy

Homework Equations



I found the following equation online: µ = z * [p * (1 - p) / n] ^ (-1/2)

The Attempt at a Solution



When I fill in this formula, I get µ = 125.5, while I think the confidence interval should be around 3 percent.
 
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If you want a 95% CI, then you want P(-a<Z<a)=0.95 where


Z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}.


So \bar{x} \pm a \frac{\sigma}{\sqrt{n}} will be a 95% CI for μ
 
Pietair said:

Homework Statement



What formula do I need to find the confidence interval, when I have got:

- Number of samples
- Level of Confidence
- The assumed (1st guess) accuracy

Homework Equations



I found the following equation online: µ = z * [p * (1 - p) / n] ^ (-1/2)
This may or may not be relevant to your problem. This formula looks vaguely related to a binomial distribution. You haven't said what the distribution is, so it's hard to say if this is something you need to use.
Pietair said:

The Attempt at a Solution



When I fill in this formula, I get µ = 125.5, while I think the confidence interval should be around 3 percent.

Again, you have provided enough information for me to tell if this is a reasonable value for µ. What you said about the confidence interval makes no sense at all. A confidence interval is an interval, with a left endpoint and a right endpoint. It is not given as a percentage.
 
Thank you for your replies.

All the information I have got considering this practice situation:

Information written down on a form will be put in a database. The information in the database can be correct (match the information written on the form) or can be incorrect (do not match the information written on the form). A mismatch occurs when the database administrator enters the wrong information (for example: putting "b" in the database when "a" is written on the form).

Now I would like to execute a sample to judge whether the data found in the database is reliable (ie consistent with the source information) or not. The database contains a total of 4000 entries. I would like to execute a sample because it is quite time consuming to check if all 4000 entries are correct or not. With this sample I would like to state something about the reliability of the entire database (4000 entries).

So, suppose I have 100 entries checked, and 2 of them do not match. Then I find that 98% of the database entries of the corresponding sample is consistent with the source information. But what can I say about the confidence level and interval of this 98% considering the entire database (4000 entries).

Thanks in advance!
 
Has anyone got an idea regarding this practical situation?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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