Finding the Curvature of a Plane Curve

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SUMMARY

The curvature of the plane curve defined by r(t) = (3cos(t))i + (3sin(t))j can be calculated using the formula κ = |r'(t) x r''(t)| / |r'(t)|^3. Although the discussion raises concerns about the applicability of the cross product in two dimensions, it is established that adding a 0k component to the vector allows for the use of the cross product in a three-dimensional context. Therefore, the curvature can be computed accurately by treating the curve as a 3D vector.

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Find the curvature of the plane curve given by r(t) = (3cost)i + (3sint)j at the point (√(2), √(7) ).

I know that κ=|r'(t) x r"(t)| / |r'(t)|^3
However, I believe that you are not allowed to do cross product unless there is an x, y, and z component and this question only has an x and y component.

In this case, am I supposed to use κ= |T'(t)/r'(t)| instead or use another formula all together?
 
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Just add a 0k to your vector and treat it as 3D if you want to use the cross product.
 

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