Finding the distance between origin and a plane.

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To find the distance from the origin to a plane defined by the equation ax + by + cz = d, one must understand that a vector perpendicular to the plane is represented by <a, b, c>. A line through the origin in the direction of this vector can be expressed with parametric equations x = at, y = bt, z = ct. The intersection of this line with the plane can be determined by substituting these parametric equations into the plane equation. The distance formula involves the normal vector's magnitude, corrected from the initial statement about distance being λn. Understanding these concepts is crucial for solving the problem accurately.
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I could not figure out the first part, though i know that distance is λn, λ being any non-zero scalar. But i could not figure out the first question it self.
 

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Well, what do you know about these things? Do you know, for example, that a vector perpendicular to the plane ax+ by+ cz= d is a multiple of <a, b, c>? Do you know that a line, through the origin, in the direction of <a, b, c> has parametric equations x= at, y= bt, z= ct? Where does the line x= at, y= bt, z= ct intersect the plane ax+ by+cz= d?

(Actually, the one thing you say you know, "that distance is λn, λ being any non-zero scalar", is not true, but I think it is a typo- you mean \lambda ||n||.)
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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