Finding the eq. of all tangent lines on a curve

Gus_Chiggins
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Homework Statement


Problem: Find the equations of all tangent lines to the curve
y = x + 2x so that also go through the point (3, 14).


2. Do not use a derivitive



3. I don't even know where to start. I searched my book there isn't really available. Any help would be much appreciated
 
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Gus_Chiggins said:

Homework Statement


Problem: Find the equations of all tangent lines to the curve
y = x + 2x so that also go through the point (3, 14).


2. Do not use a derivitive



3. I don't even know where to start. I searched my book there isn't really available. Any help would be much appreciated

Is that really supposed to be y=x+2x, or have you mis-typed something?
 
What's the correct equation? The "curve" y = x + 2x is a straight line that doesn't go through (3, 14), so no tangent can go through this point either.

Should it be y = x^2 + 2x?
 
sorry everybody,

yes I meant to say

y=x^2 + 2x

sorry
 
OK, now that we've gotten that out of the way...

Let (x_0, y_0) be the point of tangency on the graph of the curve. BTW, you have drawn the graph, right?

At the point of tangency, the tangent line has to extend from (x_0, y_0) to (3, 14).

Here is an outline of the steps you'll need to carry out for this problem:

1. Find the slope of the line from (x_0, y_0) = (x_0, x_0^2 + 2x_0) to (3, 14).
2. By calculating the derivative and evaluating it at x_0, find the slope of the tangent line.
3. Equate the value you got in step 1 with the value from step 2, and solve for x_0. (I got two values for x_0.)
4. Find the associated y value for each value of x_0 from step 3.
5. Using each point (x_0, y_0), find the equation of the line from (x_0, y_0) to (3, 14). There are two distinct equations.

Is that enough of a hint?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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