Finding the equation of a hyperbola

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Homework Help Overview

The problem involves finding the equation and sketching a hyperbola given specific vertices and asymptotes. The subject area is conic sections, specifically hyperbolas.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to determine the values of 'a' and 'b' for the hyperbola's equation. Participants question the relationship between the slope of the asymptotes and the parameters of the hyperbola.

Discussion Status

The discussion is ongoing, with participants providing hints and prompting further exploration of the relationship between 'a' and 'b'. There is no explicit consensus yet, but guidance has been offered regarding the use of the slope of the asymptotes.

Contextual Notes

Participants are working within the constraints of the problem statement and are exploring the implications of the given asymptotes and vertices.

farmd684
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Homework Statement




Problem : Find an equation and sketch in x-y coordinates for the Hyperbola with vertex (-1,7) and asymptotes y-5=+- (x+1)

The Attempt at a Solution



To find the equation of the hyperbola i have to find the length of a ( distance from center to vertex in focal axis ) and b to put them in the equation y^2/a^2 - x^2/b^2 = 1 so far i have found the center (-1,5) and vertex are (-1,7) and (-1,3) so i get a = 2 But how can i get the value of b to put it in the equation ? Thanks :)
 
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Hi farmd684! :smile:

(try using the X2 tag just above the Reply box :wink:)

If the question gives you lemons … make lemonade! :biggrin:

For y2/a2 - x2/b2 = 1, what is the slope of the asymptotes? :wink:
 
tiny-tim said:
Hi farmd684! :smile:

(try using the X2 tag just above the Reply box :wink:)

If the question gives you lemons … make lemonade! :biggrin:

For y2/a2 - x2/b2 = 1, what is the slope of the asymptotes? :wink:


Thanks for the reply :biggrin:

the slope i guess is a/b for y2/x2. Then what should i do.
 
farmd684 said:
Thanks for the reply :biggrin:

the slope i guess is a/b for y2/x2. Then what should i do.

Well, if you know a/b and you know a, then b = … ? :smile:
 
tiny-tim said:
Well, if you know a/b and you know a, then b = … ? :smile:

Thanks :smile:
 

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