Finding the filtered output signal

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Discussion Overview

The discussion revolves around finding the filtered output signal y(t) for various input signals using a causal LTI filter characterized by its frequency response H(jω). Participants explore different methods to determine y(t) based on the provided input signals and the filter's characteristics.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant seeks clarification on how to determine y(t) from the input signals and the filter's frequency response.
  • Another participant asks for the function description of H(jω) and whether it can be extracted from the graph provided.
  • A participant describes the graph of H(jω) as a straight line from (-1, 2j) to (1, -2j).
  • Multiple methods to find y(t) are proposed, including convolution, Fourier transform, and amplitude scaling, with a request for guidance on which method is most applicable.
  • One participant suggests that H(jω) could be represented as -ω, questioning its correctness.
  • Another participant reiterates the methods for finding y(t) but does not provide further clarification on their applicability.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the function description of H(jω) and the most suitable method for finding y(t). There is no consensus on the representation of H(jω) or the best approach to take.

Contextual Notes

The discussion lacks specific details about the assumptions underlying the filter's characteristics and the input signals. The mathematical steps for applying the proposed methods remain unresolved.

Who May Find This Useful

This discussion may be useful for students or practitioners in signal processing, particularly those interested in LTI systems and filtering techniques.

hxluo
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A causal LTI filter has the frequency response H(jw) shown in the graph. For each of these input signals, determine the filtered output signal y(t).

1) x(t)=exp(jt)

2) x(t)=(sin(wt))u(t)

3) X(jw)= 1 / ((jw)(6+jw))

4) X(jw)= 1 / (2+jw)

I don't understand what I have to do to find y(t), any help is appreciated, thanks
 

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what is the function description of H(j \omega)? can you extract that out of the graph?
 
nothing much in the graph, just a straight line from (-1, 2j) to (1, -2j)
 
There are many ways to find y(t):
y(t) = h(t) * x(t) convolution
y(t) = F(H(jw)X(jw)) Fourier transform of Y(jw)
y(t) = H(jw)x(t) amplitude scaling if x is an eigenfunction

Which one is most applicable? Or which have you learned?
 
yes, i learned it before, so is it correct to say H(jw)= -w?
 
y"t" = h(t) * x(t)
y"t" = f(H(jw)X(jw)
y"t" = h(jw)x(t)
 

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