Finding the force of magnetic field lines

AI Thread Summary
The discussion focuses on calculating the force on a current-carrying wire in a magnetic field using the equation F = BIL sin θ. For a wire carrying 15 A of current and measuring 17 cm in a 0.80 T magnetic field at an angle of 90°, the calculation yields F = 15 * 0.17 * 0.8 * sin(90). The correct force is determined to be 1.824 N, confirming the initial calculation. Participants clarify the multiplication process, ensuring accuracy in the solution.
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Homework Statement



A wire carrying 15 A of current has a length of 17 cm in a magnetic field of 0.80 T. The force on a current-carrying wire in a uniform magnetic field can be found using the equation F = BIL sin θ. Find the force on the wire for each of the following angles between the wire and the magnetic field lines. ( (a) 90° )

Homework Equations



F = BIL
Sin = Opposite/Hypotenuse
17 cm / 100 = .17 m

The Attempt at a Solution



F = 15*.17*.8*sin(90)
= 1.8238 N
 
Last edited:
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Looks like you did the multiplication wrong.

F = 15*.17*.8*sin(90) is correct.
 

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