Finding the height of a body through conservation of energy

AI Thread Summary
The discussion centers on calculating the height reached by an acrobat using conservation of energy principles. The first acrobat jumps with an initial velocity of 2.50 m/s, which is crucial for determining the total energy at the jump's start. The potential energy (PE) calculated for the first jumper was 3090 J, but neglecting the initial kinetic energy (KE) from the jump is incorrect. The total energy must account for both PE and KE to accurately find the height the second acrobat reaches. The conversation emphasizes the importance of considering initial velocity in energy calculations, as it impacts the overall energy balance in the system.
MichaelDunlevy
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Homework Statement



A 105 kg acrobat jumps up off a platform at a velocity of 2.50 m/s and lands on a teeter-totter 3.00 m below, where another acrobat is waiting. If the waiting acrobat has a mass of 62.5 kg, how high does she get?

Homework Equations



KE=(1/2)mv^2

PEg= mgh

The Attempt at a Solution



I calculated the PE of the first jumper (I disregarded the 2.50 m/s, it seemed unnecessary, please correct me if this is wrong), and got 3090 J.
I then plugged that into another PE=mgh equation for the second person and got 5.04 m. Is this correct?
 
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The idea is correct, but you cannot just disregard the initial velocity of 2.5 m/s.
I am sure you agree that it matters whether he jumps upwards at 2.5 m/s, just drops himself off the platform, or dives down at 2.5 m/s.

Can you explain how the initial velocity affects the total energy of the first acrobat?
 
i can, but it would be different depending on the angle that he jumped 2.5 m/s. But, no matter what, the jumper's total energy will increase because of the jump. How can I apply it to this problem without a specific direction? I need to solve the answer soon.
 
Yeah, I guess you are right, so let's assume the 2.50 m/s was the vertical component. By how much with the total energy increase?
 
doesn't that depend on how long he is in the air?
 
CompuChip said:
Yeah, I guess you are right, so let's assume the 2.50 m/s was the vertical component. By how much with the total energy increase?
doesn't that depend on how long he is in the air?
 
No, that is the beauty of using energies rather than kinematic equations.

Assuming that no energy is lost (e.g. due to friction), the sum of all kinetic and potential energy at the time of the jump should be equal to the sum of all kinetic and potential energy at the time of landing ... or at any other time, for that matter.

You already used this in your original solution, but there you assumed that all energy at the start was in the form of potential energy, and it all gets converted to kinetic energy at the intermediate point where he meets the other acrobat. You need to review the first part of that assumption.
 
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