Finding the Horizontal Force on a Bracket Supported by a Single Screw

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The discussion focuses on calculating the horizontal force exerted by a screw on a bracket supporting a plant shelf. Participants explore two methods for calculating net torque about different rotational axes, questioning the validity of their approaches. There is confusion regarding the presence of a reaction force at point B, leading to suggestions to sum forces in both horizontal and vertical directions. The conclusion emphasizes the necessity of applying Newton's Laws to determine that a horizontal force must exist despite initial assumptions. The discussion highlights the importance of correctly analyzing forces and torques in static equilibrium problems.
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Homework Statement


One side of a plant shelf
is supported by a bracket
mounted on a vertical wall
by a single screw. Ignore
the weight of the bracket.
Find the horizontal
component of the force
that the screw exerts on
the bracket when an 80.0 N
vertical force is applied as
shown

image.jpg


Homework Equations

The Attempt at a Solution


If I choose A as rotational axis, then it should be calculated as

net torque = 0
(80N)(0.05m) = (x)(0.03m)

but if a choose B as the rotational axis, then it should be calculated as

net torque = 0
(80N)(0.05m) = (x)(0.06m)

So which one is correct?

Thanks!
 
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Is there a reaction @ B?
 
I don't think so. What does it mean?
 
Well, why don't you prove it and sum forces in each direction?
 
paisiello2 said:
Well, why don't you prove it and sum forces in each direction?

That's what I can think of.
(80N)(0.05m) = (n)(0.03m)
n = 133N

but this is incorrect and I don't know why

image.jpg
 
You're taking moments. I want you to sum forces in each direction: ΣFx = 0 and ΣFy=0.
 
paisiello2 said:
You're taking moments. I want you to sum forces in each direction: ΣFx = 0 and ΣFy=0.

Just Fx = 80 from the nail? I don't think there is a horizontal force.
image.jpg
 
Just apply Newton's Laws and you will see that there must be a horizontal force.
 
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