Engineering Finding the impedance of a circuit

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To find the impedance of the circuit, the initial approach of using only the inductor's impedance is insufficient. Instead, a Thevenin analysis is suggested, but it is noted that there is no power source present, which simplifies the process. The correct method involves calculating the impedance of the parallel combination of elements between nodes b and g, and then considering the series capacitor between nodes a and b. Finally, the total impedance can be determined by calculating the equivalent impedance of the three branches in parallel between nodes a and g. This approach effectively addresses the problem without relying on Thevenin's theorem.
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Homework Statement


http://img297.imageshack.us/img297/2951/picqk5.th.jpg

I'm just trying to do part a for the moment.

Homework Equations





The Attempt at a Solution



My initial attempt was just trying to find the impedance of the 5 mH inductor and saying that would be Zin. Unfortunately that doesn't seem to be the case.

Then I tried doing a thevenin type problem where I find the impedance of all the elements to the right of the inductor, but that doesn't seem to work either.

I also just tried finding Zeq for the whole thing but that doesn't work either, hmm.
How does one find the impedance between two nodes? I would have thought that the 2nd method would have worked for sure.
 
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Thevenin Theorem should work here. Find the equivalent impedance seen from the nodes a and g.

(Hint : Fold from the right side to the left side)
 
No need to use Thevenin, since there is no power source.
Between nodes b and g there are two elements. Find the impedance of the parallel combination. Between nodes a and b there is a capacitor, that is in series with the impedance bg. Finally, calculate the impedance of the three branches in parallel between nodes a and g.
A similar reasoning can be made for items b and c.
 

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