- #1
Ibby
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A car with a total mass of 1400kg,travling at 60kmh hits a large tree and stops in 0.080 s .
2. change in momentium: m(v-u)
3. 1400(0-60)
=-84000
2. change in momentium: m(v-u)
3. 1400(0-60)
=-84000
Ibby said:got it f= ma 1400 x 16.6ms= 2.3 x 10^4 its right but isn't thsi meant to be the force or net force not the impulse?
cepheid said:That's not ma. That's m(vfinal - vinitial), which IS the impulse. The velocity change is 16.67 m/s. This is not an acceleration.
Ibby said:iam not getting it . how is the velocity chnage 16.67? isn't that its inital speed since the car stopped when it hit the tree .so its final velocity should be 0 and its inital 16.67 ?
The impulse of a stopping car is the change in momentum that occurs when the car comes to a complete stop.
The impulse of a stopping car is affected by the car's mass, velocity, and the force applied to bring it to a stop.
The impulse of a stopping car can be calculated by multiplying the force applied to stop the car by the time it takes for the car to come to a complete stop.
Understanding the impulse of a stopping car is important for designing and implementing effective safety measures, such as brakes and airbags, in cars to protect passengers in the event of a collision.
The impulse of a stopping car can be reduced by decreasing the car's mass, decreasing its velocity, or by increasing the time it takes for the car to come to a stop.