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Finding the integral of an improper fraction

  • #1

Homework Statement



Use substitution to find the integral of (12x2 + X -12)/(3x - 2)


Homework Equations





The Attempt at a Solution



I know I need to use long division to work it down to a proper fraction. That is where my real problem lies. Using long division I get that (12x2+x-12)/(3x-2) is equal to 4x-3 with a remainder of -6. I don't really understand what that means in terms of my question, especially with the remainder. Does this just mean that I have to find the integral of (4x-3) - 6/(3x-2)?
 

Answers and Replies

  • #2
gb7nash
Homework Helper
805
1
Does this just mean that I have to find the integral of (4x-3) - 6/(3x-2)?
Yes, assuming that your long division is correct. You should know how to take the integral of (4x-3) - 6/(3x-2).
 
  • #3
right on, thanks.
 

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