Use substitution to find the integral of (12x2 + X -12)/(3x - 2)
The Attempt at a Solution
I know I need to use long division to work it down to a proper fraction. That is where my real problem lies. Using long division I get that (12x2+x-12)/(3x-2) is equal to 4x-3 with a remainder of -6. I don't really understand what that means in terms of my question, especially with the remainder. Does this just mean that I have to find the integral of (4x-3) - 6/(3x-2)?