- #26

- 195

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:uhh: I thought is was [itex] \frac{du}{3}[/itex] rather than simply [itex]du[/itex] (unless that was what you meant by "du")... then:Now you can replace "x^2dx" in the original integral with "du". It is mathematically equivalent.

[itex]\int\frac{\frac{du}{3}}{u}[/itex]

[itex]\int \frac{1}{u} × \frac{du}{3}[/itex]

[itex]\int \frac{1}{u} × \frac{1}{3} du[/itex]

Damn!... I'm stuck again