Finding the Intersection of Graphs for Homework Equation

AI Thread Summary
The discussion revolves around finding the intersection of the graphs defined by the equation 1 = |(sin(x) - x)/sin(x)| * 100. A graphical approach was used to determine that the intersection occurs at approximately x = 0.244 radians. The individual expressed uncertainty about the correctness of this solution due to the potential for manipulating the equation to yield different results. Another user confirmed the intersection point using Mathematica, yielding a similar value of x ≈ 0.244097. The conversation highlights the challenges of confirming intersections in complex equations.
MrXow
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Homework Statement


1 = absolute value( (sin(x)-x)/(sin(x))) * 100


Homework Equations


Don't think there are any.


The Attempt at a Solution


I decided to do it graphically, so i graphed y=.01 and y= absolute value(1-(x/sin(x))
I got x = .244 radians for the intersection and I am just not sure if it is correct because i can manipulate the equation so that they never intersect or I can manipulate it so the point changes.
 
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Be more specific. How did you manipulate the equation?
 
MrXow said:

Homework Statement


1 = absolute value( (sin(x)-x)/(sin(x))) * 100


Homework Equations


Don't think there are any.


The Attempt at a Solution


I decided to do it graphically, so i graphed y=.01 and y= absolute value(1-(x/sin(x))
I got x = .244 radians for the intersection and I am just not sure if it is correct because i can manipulate the equation so that they never intersect or I can manipulate it so the point changes.

In order to see the problem better..

1= |(\frac{\sin(x)-x}{\sin(x)})(100)|
 
ya that's it I don't know how to do that fancy typing stuff
 
when i put it in mathematica
"FindRoot[1 == Abs[((Sin[x] - x)/Sin[x])]*100, {x, 0.1}]"
i get
{x -> 0.244097}
which makes sense
 
So, what is your question?
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
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