Finding the inverse matrix of fourier transform

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Homework Help Overview

The problem involves finding a vector \( c \) given the equation \( F4 \cdot c = y \), where \( y = (1, 0, 0, 0) \). The context is centered around the inverse of the Fourier transform matrix \( F4 \) and its application in solving for \( c \).

Discussion Character

  • Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the formulation of the inverse matrix \( F4^{-1} \) and its components, questioning the accuracy of the matrix representation and the implications of the imaginary unit \( i \). There is also a focus on the multiplication process to find \( c \) once \( F4^{-1} \) is established.

Discussion Status

Some participants have clarified their understanding of the inverse matrix and its application, while others are still seeking confirmation on the correctness of their calculations. There appears to be a productive exchange regarding the interpretation of the matrix elements and the multiplication process.

Contextual Notes

There is mention of confusion related to the imaginary components of the matrix and the initial lack of clarity regarding the provided information about \( F4 \). Some participants express uncertainty about the steps leading to the multiplication with \( y \).

tatianaiistb
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Homework Statement



If y=(1,0,0,0) and F4*c=y, find c.

Homework Equations



c=F4-1*y

The Attempt at a Solution



I'm stuck. I don't know how to get F4-1.

F4-1 = (1/N) * [1, 1, 1, 1; 1 -i (-i)^2 (-i)^3; 1 (-i)^2 (-i)^4 (-i)^6; 1 (-i)^3 (-i)^6 (-i)^9] (this is a 4x4 matrix)

N = 4

So I'm confused because from that I get,

(1/4)* [1 1 1 1; 1 -i -1 i; 1 -1 1 -1; 1 i -1 -i]
(this is a 4x4 matrix)

I know that after I get this matrix, I just have to multiply by y to get c, but that inverse matrix has me confused.

Can anyone please help? Thanks!
 
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tatianaiistb said:

Homework Statement



If y=(1,0,0,0) and F4*c=y, find c.

Homework Equations



c=F4-1*y

The Attempt at a Solution



I'm stuck. I don't know how to get F4-1.

F4-1 = (1/N) * [1, 1, 1, 1; 1 -i (-i)^2 (-i)^3; 1 (-i)^2 (-i)^4 (-i)^6; 1 (-i)^3 (-i)^6 (-i)^9] (this is a 4x4 matrix)

N = 4

So I'm confused because from that I get,

(1/4)* [1 1 1 1; 1 -i -1 i; 1 -1 1 -1; 1 i -1 -i]
(this is a 4x4 matrix)
Is what you have in the brackets above F4?
If so, use it to find the inverse, F4-1.
tatianaiistb said:
I know that after I get this matrix, I just have to multiply by y to get c, but that inverse matrix has me confused.

Can anyone please help? Thanks!
 
I do not have F4... What I'm showing is what I've worked so far for inverse of F4...
 
I figured this out... I was actually doing it right and the inverse is that matrix I specified with the i's in it. The i's were throwing me off, but when you multiply that matrix by y, the i's cancel out and you can find c. :-)
 
Your first post was not very clear on what you were given. Apparently you are given F4-1, so there's no need to find F4.
tatianaiistb said:
F4-1 = (1/N) * [1, 1, 1, 1; 1 -i (-i)^2 (-i)^3; 1 (-i)^2 (-i)^4 (-i)^6; 1 (-i)^3 (-i)^6 (-i)^9] (this is a 4x4 matrix)

N = 4
and you simplified it to get
F4-1 = (1/4)* [1 1 1 1; 1 -i -1 i; 1 -1 1 -1; 1 i -1 -i][/quote]
You know y, and you have worked out that c = F4-1y, so just carry out the multiplication of your matrix and y.

c = \frac{1}{4}\begin{bmatrix}1&1&1&1\\1&-i&-1&i\\1&-1&1&-1\\1&i&-1&-1\end{bmatrix} \begin{bmatrix}1\\0\\0\\0\end{bmatrix}
 
Thank you!
 

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