Finding the Limit of a Root Test: Calculating the Limit of a Challenging Term

  • Thread starter Thread starter MissP.25_5
  • Start date Start date
  • Tags Tags
    Root Test
MissP.25_5
Messages
329
Reaction score
0
Hello.
How do I find the limit of this term?

$$\lim_{{n}\to{\infty}}|\left(\frac{n}{n+1}\right)^{\!{n^2}}|^\frac{1}{n}$$

This is the working but I don't understand how to get the third line.

r = lim(n→∞) |[n/(n+1)]^(n^2)|^(1/n)
..= lim(n→∞) [n/(n+1)]^n
..= lim(n→∞) 1 / [(n+1)/n]^n
..= lim(n→∞) 1 / (1 + 1/n)^n
..= 1/e, by the limit definition of e.
 
Physics news on Phys.org
##\frac 1{\frac{n+1}n}=\frac n{n+1}## and ##(\frac 1a)^n = \frac 1{a^n}##, right?
 
  • Like
Likes 1 person
Erland said:
##\frac 1{\frac{n+1}n}=\frac n{n+1}## and ##(\frac 1a)^n = \frac 1a^n##, right?

Yes, but as you can see, the third line has its denominator to the power of n. That's what I don't understand. If we divide all terms with n, then what happens to the n outside the bracket?
 
Sorry, there was a typo in my reply which I corrected immediatly, but you were so quick and got the typo in your reply...
 
Erland said:
Sorry, there was a typo in my reply which I corrected immediatly, but you were so quick and got the typo in your reply...

Yeah, I was quick, haha. As soon as I submitted my post, I saw you have corrected your error. Thank you!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top