Finding the Limit of f(r) = r/(1+r^2)

  • Thread starter Thread starter hadron23
  • Start date Start date
  • Tags Tags
    Limit
hadron23
Messages
28
Reaction score
1

Homework Statement



Find the limit,

f(r) = \frac{r}{\sqrt{1+r^{2}}}

Homework Equations



None.

The Attempt at a Solution



I attempted to multiply both the top and bottom of the above equation by the denominator to cancel out the square root on the denominator, but this doens't seem to help.

Any ideas?
 
Last edited:
Physics news on Phys.org
The limit as r approaches what?
 
Can't edit it correctly above, the correct problem statement is,

\[ \lim_{r \to +\infty} \frac{r}{\sqrt{1+r^{2}}}\]
 
hadron23 said:
Can't edit it correctly above, the correct problem statement is,

\[ \lim_{r \to +\infty} \frac{r}{\sqrt{1+r^{2}}}\]

Multiply numerator and denominator by 1/r. Move the 1/r inside the radical in the denominator by squaring it. What does it look like now?
 
Got it, thanks!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top