Finding the magnitude of the eletric field of a uniformly charged rod.

AI Thread Summary
To find the electric field magnitude along the axis of a uniformly charged rod, first calculate the linear charge density (λ) using the total charge and length of the rod. A small element of the rod, represented as dq, contributes to the electric field at a point 52.1575 cm from the center. The electric field due to this element is expressed as dE = k*λ*dx/(d-x)^2, where d is the distance from the center of the rod to the point of interest. Integration of this expression from -L/2 to +L/2 will yield the total electric field at the specified point. This method allows for a precise calculation of the electric field generated by the charged rod.
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Homework Statement


"A rod of 13.1 cm long is uniformly charged and has a total charge of -23.2 micro coulombs. Determine the magnitude of the electric field along the axis of the rod at a point 52.1575 cm from the center of the rod. The Coulomb constant is 8.98755e9 N M^2/C^2. Answer in units of N/C"
I'm lost on how to go about solving this. I've tried just doing E=KQ/R^2 with R being 52.1575 cm and I tried E= KQ/(R^2+X^2)^2/3 with X= 52.1575 and R=13.1 but that's wrong to
 
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Total charge on the rod is given. Length of the rod L is given. Find the linear charge density λ.Take a small element dx of the rod at a distance x from the center. Charge on this element dq = λ*dx. Let its distance from the point where the electric field is required is (d - x) where d is the distance of the point from he center.
Field due to dq at P is
dE = k*λ*dx/(d-x)^2. Find the integration between the limits x = +L/2 to -L/2
 
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