Finding the mass of a quantity of gas given P, V, T

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To find the initial mass of oxygen in the tank, the ideal gas law equation pV=nRT is applied, using the given gauge pressure, volume, and temperature. The calculation initially yields a value for the number of moles (n) as 9.558, which is then multiplied by the molar mass of oxygen to find the mass. However, the result of 0.305856 kg is identified as incorrect, primarily due to not accounting for gauge pressure correctly. The discussion highlights the importance of understanding gauge pressure and its impact on calculations, as well as the need to consider changes in the number of moles over time due to leakage. Clarification on gauge pressure and its definition is requested for better understanding.
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Homework Statement



A welder using a tank of volume 8.00×10−2 m^3 fills it with oxygen (with a molar mass of 32.0 g/mol ) at a gauge pressure of 3.10×105 Pa and temperature of 38.9 ∘C. The tank has a small leak, and in time some of the oxygen leaks out. On a day when the temperature is 23.0 ∘C, the gauge pressure of the oxygen in the tank is 1.75×105 Pa .

Find the initial mass of oxygen.

Homework Equations



pV=nRT
where p is pressure, v is volume, n is number of mole, R is 8.31442(since p is Pa and V is in m^3), and T is kelvin.
m total = n*M ; where n is number of moles and M is molar mass.

The Attempt at a Solution


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pV = nRT

= 3.10 * 10^5 * 8.00 * 10^(-2) = n*8.314472* 312.05

n = 9.558

9.558 * 0.032 kg/mol = 0.305856

however, 0.305856 is incorrect. where did i make mistake?
 
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Gauge pressure.
 
Bystander said:
Gauge pressure.
thank you for replying, but can you please explain more specific, please?
 
What is the definition of "gauge pressure?"
 
Mentor's note: Thread title has been changed to make it descriptive of the problem.
 
Did you take cognizance of the fact that n has changed?
 
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