MHB Finding the measure of Triangle ABC

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A = 46 degrees

b = 8

I don't even know how to start this and I'm really confused. I've already labeled A and b but I really have no clue on how to continue. .-. Can someone please explain this very carefully to me and use simple terms?

I've been trying to do this problem and I was told that I start it by doing 10 x sin 18, but I'm not really sure why that is done. So far I got a =0.053, I'm not sure if that's right or wrong so yeah. .-. I need to find a, b and c and I'm confused on what to multiply.
 
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What relationship must hold between $\angle A$ and $\angle B$?
 
MarkFL said:
What relationship must hold between $\angle A$ and $\angle B$?

The directions say " Solve Triangle ABC using the diagram and the given measurements. "

It's referring to the lowercase b, which is a side of the triangle in the example diagram.
 
Mizu said:
The directions say " Solve Triangle ABC using the diagram and the given measurements. "

It's referring to the lowercase b, which is a side of the triangle in the example diagram.

I am assuming you are to find the measure of all angles and sides. Since it is a right triangle, and you know the measure of one of the acute angles, what must the measure of the other be?

Once you know all 3 angles, and you know at least 1 side's measure, you can then use the Law of Sines to find the measures of the unknown sides.
 
Angles sum = 180º
B = 180º - 90º - A = 44º
Use sine law for a and c.
a = 8.28 and c = 11.52
Use Pythagoraem's theoreme for area.
area = 33.14 ( ² )
 

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