Finding the Mistake in Calculating Charge on a Capacitor with a Shorted Wire

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SUMMARY

The discussion centers on the calculation of charge on capacitors in a circuit where a wire shorts a combination of 2μF and 3μF capacitors. Participants confirm that with a 6V drop across a 1μF capacitor, the charge on the 2μF capacitor is indeed 0, as the potential across it is 0 due to the short. This conclusion is supported by multiple contributors, indicating that the book's answer is incorrect.

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Homework Statement


capacitor2.jpg


Homework Equations

The Attempt at a Solution


[/B]
Sorry for the unclear image .

There is a wire across the combination of 2μF and 3μF capacitors which means the two capacitors are shorted . The whole of 6V drops across the 1μF capacitor . In that case charge on the 2μF capacitor should be 0 . But this is not an option .

What is my mistake ?
 

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I think it's a wrong answer by the book honestly.
 
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Hydrous Caperilla said:
I think it's a wrong answer by the book honestly.

You mean none of the options are correct ?

Do you agree there would be 0 charge on 2μF capacitor ?
 
yea because the potential across the capacitor is 0
 
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Thanks !
 

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