- #1
Dellis
- 90
- 0
Hi, I need some guidance regarding this exercise, I attached a visual representation of the exercise
Find the Resultant Force for the following system of forces shown
FORCES SHOWN on a Vector:
F1= 5 kips on the X quadrant in a 60 degree angle
F2= 5 kips straight down on the Y axis
F3= 8 kips on the X quadrant in a 30 degree angle
These right?
Rx= [tex]\Sigma[/tex]Fx= F1 + F2 + F3
Ry=[tex]\Sigma[/tex]Fy= F1 + F2+ F3
(theta)Qx= Tan- Ry/Rx
I want to know if I am going in the right direction, if not please guide me, this is what I tried.
Rx= [tex]\Sigma[/tex]Fx= F1 + F2 + F3
=+5(sin 60 )- 5 + 8(cos 30 )
= -6.16 kips
Ry=[tex]\Sigma[/tex]Fy= F1 + F2+ F3
= -5( sin 60)-5 + 8 (cos 30)
= -8.571 kips
Homework Statement
Find the Resultant Force for the following system of forces shown
FORCES SHOWN on a Vector:
F1= 5 kips on the X quadrant in a 60 degree angle
F2= 5 kips straight down on the Y axis
F3= 8 kips on the X quadrant in a 30 degree angle
Homework Equations
These right?
Rx= [tex]\Sigma[/tex]Fx= F1 + F2 + F3
Ry=[tex]\Sigma[/tex]Fy= F1 + F2+ F3
(theta)Qx= Tan- Ry/Rx
The Attempt at a Solution
I want to know if I am going in the right direction, if not please guide me, this is what I tried.
Rx= [tex]\Sigma[/tex]Fx= F1 + F2 + F3
=+5(sin 60 )- 5 + 8(cos 30 )
= -6.16 kips
Ry=[tex]\Sigma[/tex]Fy= F1 + F2+ F3
= -5( sin 60)-5 + 8 (cos 30)
= -8.571 kips
Attachments
Last edited: