Finding the Shear and Compressive Forces for a Running Rhino

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SUMMARY

The discussion focuses on calculating the shear and compressive forces acting on a black rhinoceros weighing 1400 Kg, which is running at a speed of 11 m/s and needs to stop in 1 second. The rhino positions its front legs at a 60-degree angle to the ground to achieve this. The user initially struggles with applying the Pythagorean theorem and the principles of force calculation, specifically using F=ma to determine the horizontal force of 15400 N. Ultimately, the user resolves their confusion regarding the application of trigonometric functions to find the necessary forces.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Basic knowledge of trigonometry, specifically SOHCAHTOA
  • Familiarity with vector resolution in physics
  • Ability to draw and interpret force diagrams
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  • Study vector resolution techniques in physics
  • Learn about calculating forces in dynamic systems
  • Explore the application of trigonometric functions in force analysis
  • Review examples of force calculations involving angles and mass
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This discussion is beneficial for physics students, engineers, and anyone interested in biomechanics or force analysis in dynamic scenarios.

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A black Rhinoceros weighs in at 1400 Kg and is running 11 m/s and has to stop in 1s or fall into a ravine. In order to accomplish this, the Rhino places his front legs directly out in front of him at a 60degree angle to the ground. What is the compressive and shear forces that the front legs must resist to accomplish this assuming that all of the force is transmitted through the front limbs.



D = delta V/t; a^2+b^2=c^2



I drew a diagram so I have a triangle with the vectors. The resistance vectors are up and right for a resulting vector 60 deg North of West. I think I use pythg. to find compressive force but am lost on shear. I think once I find shear I plug that in for the vertical vector and the horizontal vector is 11m/s^2. I have no idea where to start though to find shear.


Thanks. :-)
 
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Ok. So now I have F=ma so the horizontal force is 15400 N and the angle is 60 so I need to find the other side and the hypoteneuse I think. Any help? I think I am drawing it wrong because I know that I use sohcahtoa but with which angle?
 
I figured it out thank you please close.
 

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