Finding the Slope of a Tangent Line to f(x) at (2,3)

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Homework Statement



the line tangent to the graph of f(x) = x-1/x at (2,3) has what slope?

The Attempt at a Solution



Same story with this problem, I remember doing it but can't remember how to attack the problem. can someone give me a good first step to go off of?
 
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The slope of the tangent line to a curve, at any point, is the value of the derivative their. That's often taken as a definition of derivative. In order to differentiate, I would write that as f(x)= x- x-1.
 
1 + 1/4 = 5/4, gotcha.

so the 3/2 on the y-axis has no role in determining the final answer?
 
Of minor note, the graph doesn't actually pass through (2,3), but I'll assume it's a typo (though it would be a mean trick question)

The value of f(x) is pretty much irrelevant to the slope of the tangent line, yes. (in fact, note you can add any constant to f, making it f(x)+c, and it will still have the same derivative.)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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